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r=15cm
α=200°
l=(α:360°)*2πr
l= (200°:360°)*2π15≈0,55*30π=16,5π = 51,81cm
pole wyc koła
P=(α:360°)*πr²
P=(200°:360°)*π15²≈0,55*255π=123,75π =388,575cm²
kąt alfa = 200 stopni
długość łuku- alfa/360°* 2лr
l= 200/360 * 2л15= 5/9* 30л= 150/9л= 16,6 л cm
pole wycinka koła- alfa/360°* лr²
P= 200/360*15²л= 5/9*225= 125 л cm²