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t sehingga h>8:
h > 8
10t - 2t² > 8
0 > 2t² - 10t + 8
0 > (2t - 8)(t - 1)
1 < t < 4
h max terjadi saat dh/dt = 0
h = 10t - 2t²
dh = (10 - 4t) dt
dh/dt = 10 - 4t
0 = 10 - 4t
4t = 10
t = 5/2, h maks saat t = 5/2 detik
h(t) = 10t - 2t²
h(5/2) = 10(5/2) - 2(5/2)²
= 50/2 - 50/4
= 50/4
= 25/2 meter
8 < 10t - 2t²
0 < -8 + 10t - 2t²
0 < 2t² -10t + 8
2t² -10t + 8 > 0
(2t - 2) (t - 4) > 0
t < 1 ∨ t > 4
t < 1 tidak memenuhi
Jadi bola berada di atas 8 meter setelah lebih dari 4 detik.