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D= n . (n-3) : 2
9= n. (n-3) : 2
9 . 2 = n . (n - 3)
18 = n² - 3n
0 = n² - 3n - 18
a= 1 b= -3 c= -18
Aplicar la formula: (-b +-√b² - 4.a.c) ÷2.a=
=(3 +- √9 - 4.1.-18) ÷2.1 =
=(3 +- √9+72 ) ÷2 =
= (3 +- √81) ÷ 2 = (3+9)÷ 2= 12 ÷ 2 = 6
Por lo tanto el cuadrilàtero es un hexàgono