podaj wzór elementarny tlenku E₂O₃ w którym stosunek masy E:O=1,125:1
E2O3 = 1,125 :12x: 48 = 54 : 4854 :2= 27x = 27E= Glin ( Al)Al2O3
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E2O3 = 1,125 :1
2x: 48 = 54 : 48
54 :2= 27
x = 27
E= Glin ( Al)
Al2O3