Podaj wszystkie możliwe rozwiazania w liczbach calkowitych równania:
2a+3b=2
2 a + 3 b = 2
3 b = 2 - 2 a
3 b = 2*( 1 - a)
b = [ 2*(1 - a)]/3
1 - a = 3*k
a = 1 - 3 *k
===========
b = [ 2*3 k]/3 = 2 k
====================
Odp. a = 1 - 3 k ; b = 2 k , gdzie k jest liczbą całkowitą
===========================================================
Np.( 1; 0), ( -2; 2),( -5;4),( -8; 6), ...
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2 a + 3 b = 2
3 b = 2 - 2 a
3 b = 2*( 1 - a)
b = [ 2*(1 - a)]/3
1 - a = 3*k
a = 1 - 3 *k
===========
b = [ 2*3 k]/3 = 2 k
====================
Odp. a = 1 - 3 k ; b = 2 k , gdzie k jest liczbą całkowitą
===========================================================
Np.( 1; 0), ( -2; 2),( -5;4),( -8; 6), ...