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f(x) < -10 ⇔ x² - x - 12 < -10
x² - x - 2 < 0
Δ = 1 + 8 = 9 , √Δ = 3 , x1 = 1 - 3 / 2 = -1, x2 = 1 + 3 / 2 = 2
a = 1 > 0 parabolka ramionkami do góry, a więc x∈(-1, 2), a liczby całkowite należące do tego przedziału to 0 i 1
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