n=1,3
β=30°
α=?
sin(α)/sin(β)=n
sin(α)=n·sin(β)
α=arcsin(n·sin(β))
α=arcsin(1,3*sin(30))
α≈40,5°
[tex]Dane:\\\beta = 30^{o}\\sin30^{o} = 0,5\\n = 1,3\\Szukane:\\\alpha = ?[/tex]
Z prawa załamania:
[tex]\frac{sin \ \alpha}{sin \ \beta} = n\\\\sin \ \alpha = nsin \ \beta\\\\sin \ \alpha = 1,3\cdot0,5\\\\sin \ \alpha = 0,65\\\\\huge\boxed{\alpha \approx40,5^{o}}[/tex]
Odp. Promień światła powinien padać z powietrza do wody pod kątem ok. 40,5°.
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n=1,3
β=30°
α=?
sin(α)/sin(β)=n
sin(α)=n·sin(β)
α=arcsin(n·sin(β))
α=arcsin(1,3*sin(30))
α≈40,5°
[tex]Dane:\\\beta = 30^{o}\\sin30^{o} = 0,5\\n = 1,3\\Szukane:\\\alpha = ?[/tex]
Z prawa załamania:
[tex]\frac{sin \ \alpha}{sin \ \beta} = n\\\\sin \ \alpha = nsin \ \beta\\\\sin \ \alpha = 1,3\cdot0,5\\\\sin \ \alpha = 0,65\\\\\huge\boxed{\alpha \approx40,5^{o}}[/tex]
Odp. Promień światła powinien padać z powietrza do wody pod kątem ok. 40,5°.