Question

po prostu pomóżcie z góry dziękuje

Answer 1

Odpowiedź:

b)

sinα = 2/2√5 = 1/√5 = √5/5

cosα = 4/2√5 = 2/√5 = 2√5/5

tgα = 2/4 = 1/2

sinβ = 4/2√5 = 2/√5 = 2√5/5

cosβ = 2/2√5 = 1/√5 = √5/5

tgβ = 4/2 = 2

c)

sinα = 2√3/5

cosα = √13/5

tgα = 2√3/√13 = 2√3 * √13/13 = 2√39/13

sinβ = √13/5

cosβ = 2√3/5

tgβ = √13/2√3 = √13 * √3/(2 * 3) = √39/6