1.
a. 1.204 x 10²³ molekul
b. Jumlah atom :
Jumlah atom H = 2.048 x 10²³ atom H
Jumlah atom S = 1.024 x 10²³ atom S
Jumlah atom O = 4.816 x 10²³ atom O
2. 2.408 x 10²³ molekul.
3. 48.872 L
4. 34 g/mol
1. 0.2 mol asam sulfat
maka
a. jumlah partikel asam sulfat = 0.2 mol x 6.02 x 10²³ molekul/mol
jumlah partikel = 1.204 x 10²³ molekul
Jumlah atom H = 2 x (jumlah partikel H₂SO₄) = 2.048 x 10²³ atom H
Jumlah atom S = 1 x (jumlah partikel H₂SO₄) = 1.024 x 10²³ atom S
Jumlah atom O = 4 x (jumlah partikel H₂SO₄) = 4.816 x 10²³ atom O
2. V = 8.96 L
Jumlah molekul = V : 22.4 L/mol x 6.02 x 10²³ molekul/mol
Jumlah molekul = 8.96 : 22.4 x 6.02 x 10²³ = 2.408 x 10²³ molekul.
3. mol = 2 mol | R = 0.082 | T = 298 K | P = 1 atm
P.V = n.R.T
V = n (RT/P) = 2 mol (0.082 x 298)/1 =48.872 L
4. massa = 4.25 g | V = 2.8 L
Mr = massa : mol
Mr = massa : (V / 22.4)
Mr = 4.25 : (2.8 /22.4) = 34 g/mol
Konsep Mol : brainly.co.id/tugas/2623883
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Jawaban
1.
a. 1.204 x 10²³ molekul
b. Jumlah atom :
Jumlah atom H = 2.048 x 10²³ atom H
Jumlah atom S = 1.024 x 10²³ atom S
Jumlah atom O = 4.816 x 10²³ atom O
2. 2.408 x 10²³ molekul.
3. 48.872 L
4. 34 g/mol
Penjelasan
1. 0.2 mol asam sulfat
maka
a. jumlah partikel asam sulfat = 0.2 mol x 6.02 x 10²³ molekul/mol
jumlah partikel = 1.204 x 10²³ molekul
b. Jumlah atom :
Jumlah atom H = 2 x (jumlah partikel H₂SO₄) = 2.048 x 10²³ atom H
Jumlah atom S = 1 x (jumlah partikel H₂SO₄) = 1.024 x 10²³ atom S
Jumlah atom O = 4 x (jumlah partikel H₂SO₄) = 4.816 x 10²³ atom O
2. V = 8.96 L
Jumlah molekul = V : 22.4 L/mol x 6.02 x 10²³ molekul/mol
Jumlah molekul = 8.96 : 22.4 x 6.02 x 10²³ = 2.408 x 10²³ molekul.
3. mol = 2 mol | R = 0.082 | T = 298 K | P = 1 atm
P.V = n.R.T
V = n (RT/P) = 2 mol (0.082 x 298)/1 =48.872 L
4. massa = 4.25 g | V = 2.8 L
Mr = massa : mol
Mr = massa : (V / 22.4)
Mr = 4.25 : (2.8 /22.4) = 34 g/mol
Pelajari Lebih Lanjut
Konsep Mol : brainly.co.id/tugas/2623883