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u3=10
u5=8
3ke 5 = 2
10 - 8 = 2
per lompat -1
suku pertama=
u3=u1+(3-1)b
u3=12+(2)-1
=12-2
=10
brarti bedanya -1
terus suku pertamanya 12
2.u5 = 18
u2+u4=20
lompat 4
artmatika
u4=14
u3=10
u2=6
14+6=20
3.u8=21
u5=33
u50?
8-5=3
33-21=12
12:3=4
lompatnya -4
=
u1=47
u2=45
u3=41
u4=37
u50=47+(49)-4
=47-196
=-149
4.24,20,16
lompat 4
u4=12
24+20+16+12=72
=4 bilangan
5.u5=22
u1+u2+u3=30
lompat 4
14+10+6=30
u15=14+(14)4
=14+56
=70