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Diketahui :
F1 = 150 μN = 150x10⁻⁶ N
r2 = 20 mm = 2x10⁻² m
F2 = 6 μN = 6x10⁻⁶ N
Ditanyakan : r1 ?
Dijawab :
F1/F2 = kQ1Q2/r1² / k Q1Q2/r2² --------------> k Q1Q2 habis dibagi
F1/F2 = 1/r₁² / 1/r₂²
F1/F2 = r₂² / r₁²
150x10⁻⁶/ 6x10⁻⁶ = (2x10⁻²)² /r₁²
25 = 4x10⁻⁴ /r₁²
r₁² = 4x10⁻⁴ /25
r1² = √0,16x10⁻²
r1 = √16x10⁻⁴
r1 = 4x10⁻² m
r1 = 0,2 mm
Nomor 11
Diketahui :
Q1 = 100 c = 10²
Q2 = 200 C = 2x10²
F = 1,8x10⁵
Ditanyakan : r ?
Dijawan :
F = k Q1Q2/r²
1,8x10⁵ = 9x10⁹ x 10² x2x10² / r²
1,8x10⁵ = 18x10¹³/r²
r² = 1,8x10¹⁴ / 1,8x10⁵
r = √10⁹