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Jawab1.
lim(x->∞) (2 - 6x)^3/ (4x+1)^3
(bagi kooef pangkay tertinggi)
x--> ∞ = (-6/4)^3 = (-3/2)^3 = -27 /8
2.
f'(x) = [ (2x+4)(2x-1) - 2(x^2 + 4x)] (2x -1)^2
f'(2) --> x = 2
f' (2) = [ (12)(3) - 2(12}/[3)^2 = (36 -24)/ (27)
f' (2) = 12/27 = 4/9