Question

please bantuin ......​

Answer 1

(9x^(-1/3 + 1))/(-1/3 + 1) + C (C = konstanta)
(9x^2/3)/(2/3) + C
9x^2/3 x 3/2 + C
27/2x^2/3 + C.

Jadi, hasil integral tersebut adalah 27/2x pangkat 2/3 + C.

Semoga membantu.

Answer 2

Penjelasan dengan langkah-langkah:

Integral

[tex]=\int 9x^{-\frac{1}{3}} dx[/tex]

[tex]=9\times\int x^{-\frac{1}{3}} dx[/tex]

[tex]= 9\times \frac{x^{-\frac{1}{3} + 1}}{ - \frac{1}{3} + 1 }[/tex]

[tex]= 9\times \frac{x^{\frac{2}{3}}}{ \frac{2}{3} }[/tex]

[tex] = 9 \times \frac{3 {x}^{ \frac{2}{3} } }{2} [/tex]

[tex] = \frac{27}{2}\sqrt[3]{ {x}^{2} } + C[/tex]