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Cu + H2SO4 → CuSO4 + SO2 + H2O
Cu → Cu^2+ + 2e^- | ·1
SO4^2- + 4H^+ + 2e^- → SO2 + 2H2O | ·1
Cu + 2H2SO4 → CuSO4 + SO2 + 2H2O
Masa molowa miedzi to 63.5 g/mol. Reakcja i proporcja:
63.5 g 22.4 dm³
Cu + H2SO4 → CuSO4 + SO2 + H2O
5 g x
x = 1.76 dm³ SO2
proszę :)