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m = 10 kg
T₁ = 4000 C
T₂ = 1530 C temp. krzepnięcia żelaza
T₃ = 200 C
ck = 270000 J /kg
cw = 460 J/kg * C
Q = Q₁ + Q₂ + Q₃
Q₁ = m * cw * ( T₁ - T₂)
Q₁ = 10 kg * 460 J/kg * C * ( 4000 C - 1530 C ) = 11,36 MJ
Q₂ = m * ck
Q₂ = 10 kg * 270000 J/kg = 2700000 J = 2,7 MJ
Q₃ = m * cw * (T₂ - T₃ )
Q₃ = 10 kg * 460 J/kg * C * ( 1530 - 200 C ) = 6,12 MJ
Q = 20,18 MJ
bryłka ochładza się do tep, krzepnięcia = Q₁; krzepnie = Q₂ ; ochładza się do temp. 200 C = Q₃
zad.2.
q₁ = 5 μC = 5 *10⁻⁶ C
q₂ = 2 μC = 2 *10⁻⁶ C
r = 0,08 m = 8 *10⁻² m
k = 9 *10⁹ N * m² /C²
zad.3.
t = 3 min = 3 *60 s = 180 s
W = 360000 J