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proszę o rozwiązanie dwóch układów równań:
1)
2) 6x-8= 10(3x-12)
1
7x-1/3 * 2x+1/5
5(7x-1) * 3(2x+1)
(35x-5) * (6x+1)
210x +35-30x-5
180x+30
180x=-30/:180
x=-30/180= -1/60
2
6x-8=10(3x-12)
6x-8=30x-120
6x-30=-120+8
-24x=-112/ : (-24)
x= 4 14/24
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1
7x-1/3 * 2x+1/5
5(7x-1) * 3(2x+1)
(35x-5) * (6x+1)
210x +35-30x-5
180x+30
180x=-30/:180
x=-30/180= -1/60
2
6x-8=10(3x-12)
6x-8=30x-120
6x-30=-120+8
-24x=-112/ : (-24)
x= 4 14/24