PILNE Oblicz pole powierzchni całkowitej stożka o średnicy 1m i wysokości 15 dm
d = 1m = 10dm
r = 5dm
H = 15dm
Pp = 2πr
Pp = 2 * π * 5dm
Pp = 10πdm² = 31,4dm²
H² + r² = l²
15² + 5² = l²
225 + 25 = l²
250 = l² | √
√250 = l = 5√10dm
Pb = πrl
Pb = π * 5dm * 5√10dm
Pb = 25√10πdm² = 78,5√10dm²
Pc = Pp + Pb
Pc = 31,4dm² + 78,5√10dm²
Pozdrawiam! ;D
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
d = 1m = 10dm
r = 5dm
H = 15dm
Pp = 2πr
Pp = 2 * π * 5dm
Pp = 10πdm² = 31,4dm²
H² + r² = l²
15² + 5² = l²
225 + 25 = l²
250 = l² | √
√250 = l = 5√10dm
Pb = πrl
Pb = π * 5dm * 5√10dm
Pb = 25√10πdm² = 78,5√10dm²
Pc = Pp + Pb
Pc = 31,4dm² + 78,5√10dm²
Pozdrawiam! ;D