PILNE! MOJA ZNAJOMA WŁAŚNIE PISZE SPRAWDZIAN!!! rozwiąż równanie:
a) 4x kwadrat - x kwadrat + 12x - 3 = 0
b) (6x kwadrat + 7x - 3) (x kwadrat - 5x + 6) = 0
c) (x+2) kreska ułamkowa (3x + 5) = (3x + 5) kreska ułamkowa (2x + 4)
OBLICZ X
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a)
4x^2-x^2+12x-3=0
3x^2+12x-3=0
Δ=144-4*3*(-3)
Δ=144+36
Δ=180
√180=√10*√18=√10*3√2=3√20=3√4*√5=6√5
x1=(-12+6√5)/6=3(-4+2√5)/6=(-4+2√5)/2=-2+√5
x2=(-12-6√5)/6=3(-4-2√5)/6=-4-2√5/2=-2-√5
b)
(6x^2+7x-3)(x^2-5x+6)=0
6x^2+7x-3=0
Δ=49-4*6*(-3)
Δ=49+72
Δ=121 √121=11
x1=(-7-11)/12=-18/12=-1 i 1/2
x2=(-7+11)/12=4/12=2/6=1/3
x^2-5x+6=0
Δ=25-4*1*6
Δ=25-24 Δ=1 √1=1
x1=(5+1)/2=3
x2=(5-1)/2=2
c)
(x+2)/(3x+5)=(3x+5)/(2x+4)
3x+5≠0
3x≠-5
x≠-5/3
2x+4≠0
2x≠-4
x≠-2
(2x+4)(x+2)=(3x+5)(3x+5)
2x^2+4x+4x+8=9x^2+15x+15x+25
2x^2+8x+8=9x^2+30x+25 /-25
2x^2+8x-17=9x^2+30x /-30x
2x^2-22x-17=9x^2 /-9x^2
-7x^2-22x-17=0
Δ=484-4*(-7)*(-17)
Δ=484-476
Δ=8
√8=2√2
x1=(22-2√2)/-14=-2(-11+√2)/-14=(-11+√2)/7
x2=(22+2√2)/-14=-2(-11-√2)/-14=(-11-√2)/7
a)
b)
c)
Pozdrawiam :)