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Kso = [Ba²⁺][CrO₄²⁻]
[Ba²⁺] = [CrO₄²⁻]
x² = 3,6 *10⁻¹¹
x = √3,6 *10⁻¹¹ =√0,36*10⁻¹⁰
Rozpuszczalność chromianu wynosi: x = 0,6 *10⁻⁵ mol/dm³