Odpowiedź:
Szczegółowe wyjaśnienie:
f)3
g)-1
h)-1/2
i)5
j)0.4
g)30 : 3 + 7 = 10 + 7 = 17
h)-3/18 = -1/6
i)[tex]\sqrt{3} * \sqrt{27} = \sqrt{3} *\sqrt{3} * \sqrt{9} = \sqrt{9} * \sqrt{9 } = 9[/tex]
[tex]f)\ \ \sqrt[3]{27}=\sqrt[3]{3^3}=3\\\\g)\ \ \sqrt[3]{-1}=-\sqrt[3]{1}=-1\\\\h)\ \ \sqrt[3]{-\frac{1}{8}}=-\sqrt[3]{\frac{1}{8}}=-\frac{1}{2}\\\\i)\ \ \sqrt[3]{125}=\sqrt[3]{5^3}=5\\\\j)\ \ \sqrt[3]{0,064}=\sqrt[3]{\frac{64}{1000}}=\sqrt[3]{\frac{8}{125}}=\frac{2}{5}\\\\\\\\g)\ \ \sqrt{900}:\sqrt[3]{27}+\sqrt{49}=30:3+7=10+7=17\\\\h)\ \ \frac{\sqrt[3]{-27}}{18}=\frac{-3}{18}=-\frac{1}{6}\\\\i)\ \ \sqrt{3}\cdot\sqrt{27}=\sqrt{3\cdot27}=\sqrt{81}=9[/tex]
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Odpowiedź:
Szczegółowe wyjaśnienie:
f)3
g)-1
h)-1/2
i)5
j)0.4
g)30 : 3 + 7 = 10 + 7 = 17
h)-3/18 = -1/6
i)[tex]\sqrt{3} * \sqrt{27} = \sqrt{3} *\sqrt{3} * \sqrt{9} = \sqrt{9} * \sqrt{9 } = 9[/tex]
[tex]f)\ \ \sqrt[3]{27}=\sqrt[3]{3^3}=3\\\\g)\ \ \sqrt[3]{-1}=-\sqrt[3]{1}=-1\\\\h)\ \ \sqrt[3]{-\frac{1}{8}}=-\sqrt[3]{\frac{1}{8}}=-\frac{1}{2}\\\\i)\ \ \sqrt[3]{125}=\sqrt[3]{5^3}=5\\\\j)\ \ \sqrt[3]{0,064}=\sqrt[3]{\frac{64}{1000}}=\sqrt[3]{\frac{8}{125}}=\frac{2}{5}\\\\\\\\g)\ \ \sqrt{900}:\sqrt[3]{27}+\sqrt{49}=30:3+7=10+7=17\\\\h)\ \ \frac{\sqrt[3]{-27}}{18}=\frac{-3}{18}=-\frac{1}{6}\\\\i)\ \ \sqrt{3}\cdot\sqrt{27}=\sqrt{3\cdot27}=\sqrt{81}=9[/tex]