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Koło opisane:
R = a
P = πR² = πa²
Koło wpisane:
r = (a√3)/2
p = πr² = π(3a²/4)
P - p = 16π
πa² - π(3a²/4) = 16π
a² - 3a²/4 = 16
4a² - 3a² = 64
a² = 64
a = 8
Bok sześciokąta jest równy 8.