Question

PH = 1-log 2 = [H+]?
pH = 12+log 5,04 = [H+]?

tolong jelasin lengkap ya, kenapa kok bisa jadi segitu [H+] nya.

Answer 1

PH = 1 - log 2
 - log [H⁺] = 1 - log 2
               = log 10 - log 2
               = - ( log 10⁻¹ + log 2)
               = - ( log 2.10⁻¹)
               = - log 2.10⁻¹
        [H⁺] = 2.10⁻¹ M

pH = 12 + log 5,04 = 14 - pOH
pOH = 2 - log 5,04
- log [OH⁺] = log 10² - log 5,04
                = - (log10⁻² + log 5,04)
                = - log 2.10⁻²
       [OH⁻] = 2.10⁻² M