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Transformasi GeometriMatematika XII
Pembahasan terlampir
1) L1 = 32
.
L2 = | L1 x Det T1 x det T2 |
L2 = |32 {2(1/4) - 1/2 (5/8)}{4(1) - 8(1)}|
L2 = |32 (1/2 - 5/16) (-4)|
L2 = |32 (3/16)(-4)|
L2 = | -24|
L2 = 24 cm²
2. L1 = luas persegi panjang semula
L2 = | L1 x det T1 x det 2|
L2 = | L1 (2(1) - 4(1)) (3²)\
L2 = | L1 (-2)(9)|
L2 = 18 L1