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Verified answer
GGL total
ΣE = E1 + E2 + E3
ΣE = -8 + 6 + 8 = 6 V
Hambatan dalam total
Σr = 0,5 + 0,5 + 1 = 2 ohm
Hambatan luar total
ΣR = 2 + 2 + 3 + 4 + 4 + 8
ΣR = 23 ohm
Kuat arus
i = ΣE / (ΣR + Σr)
i = 6 / (23 + 2)
i = 0,24 A
searah putaran jarum jam
Energi listrik pada hambatan luar
W = i² ΣR t
W = 0,24² • 23 • 30
W = 39,744 J
Energi listrik pada hambatan dalam (hilang memjadi panas)
Wr = 0,24 • 2 • 30 = 3,456 J
Energi total
W = V i t
W = 6 • 0,24 • 30 = 43,2 J
atau
W = 39,744 + 3,456 = 43,2 J
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