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r = |(3(2) - 4(-3) + 2)/√(3² + 4²))|
= |(6 + 12 + 2)/5)|
= 4
persamaan lingkaran pusat (2,-3) dan r = 4 adalah
(x - 2)² + (y + 3)² = 16
atau
x² + y² - 4x + 6y - 3 = 0