Question

Persamaan garis yang tegak lurus dengan garis y-3x-1=0 dan melalui titik (-1,2) tolong di jwb cepat yea soalny besok udah di kumpul

Answer 1

Y=3x+1
m1=3
⊥ m2 ⇒ m1 x m2 = -1
m2 = -1/3

y-2=-1/3(x+1)
3y-6=-x-1
x+3y-5=0

Answer 2

Y = 3x + 1
m = 3
m1 × m2 = -1
3 × m2 = -1
m2 = -1/3

y - y1 = m (x - x1)
y - 2 = -1/3 (x + 1) --> kali 3
3y - 6 = -1 (x + 1)
3y - 6 = -x - 1
3y + x = -1 + 6
3y + x = 5