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Verified answer
Persamaan garis yg melalui titik (2,-3) dan (5,4)y-y1/y2-y1 = x-x1/x2-x1
y-(-3)/4-(-3) = x-2/5-2
y+3/7 = x-2/3
3.(y+3) = 7.(x-2)
3y+9 = 7x-14
3y = 7x-14-9
3y = 7x-23
y = 7/3x-23/3
m1 = koefisien x
= 7/3
Sejajar, maka:
m2 = m1
m2 = 7/3
Persamaan garis yg melalui titik (7,2)
y-y1 = m.(x-x1)
y-2 = 7/3.(x-7)
y-2 = 7/3x-49/3
y = 7/3x-49/3+2
y = 7/3x-43/3 (kali 3 kedua ruas)
3y = 7x-43
7x-3y = 43