" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
MAPEL = MATEMATIKAKELAS = 8
BAB = PERSAMAAN GARIS LURUS
diketahui =
x1 = 3
y1 = 2
tegak lurus dengan garis 3x + y + 2 = 0
ditanya = pers.garis??
- mencari gradien
bentuk umum
➡ ax + by + c = 0
m1 = -(a/b)
➡ 3x + y + 2 = 0
m1 = -(3/1)
m1 = -3
karena tegak lurus maka :
m1 . m2 = -1
-3 . m2 = -1
m2 = -1/-3
m2 = 1/3
pers. garis :
semoga membantu
Verified answer
3x +y +2 = 0y = -3x + 2
sehingga m adalah -3
jika ditegak luruskan menjadi
y-y₁ = m(x-x₁)
y-2 = ¹/₃(x-3)
y-2 = ¹/₃x -1
y = ¹/₃x -1 +2
y = ¹/₃x +1
atau
y = ¹/₃x +³/₃
3y = x +3
persamaannya adalah y = ¹/₃x +1
atau 3y = x +3