Question

Persamaan garis yang melalui titik (-3,-3)dan sejajar garis 4X-3y+6=0
A.4X-3y+1=0
B.4X-3y+3=0
C.3X-4y+21=0
D.-3X-4y-21=0
*Please pakai cara kerja yh!!

Answer 1

Titik (-3,-3)
garis 4x-3y+6 = 0
m = -a/b = -4/-3 = 4/3

syarat sejajar ⇒ m₁=m₂

persamaan garis lurusnya
y-y₁ = m(x-x₁)
y-(-3) = 4/3(x-(-3))
y+3 = 4/3(x+3)
3(y+3) = 3[4/3(x+3)]
3y+9 = 4(x+3)
3y+9 = 4x+12
-4x+3y+9-12 = 0
-4x+3y-3 = 0