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Verified answer
Garis y = -6x + 2memilki gradien m1 = -6
syarat tegak lurus
m1 . m2 = -1
-6 . m2 = -1
m2 = 1/6
jadi pers. garisnya yang melalui (-3,-3) adalah
y + 3 = (1/6) (x + 3)
y + 3 = x/6 + 3/6
6y + 18 = x + 3
x - 6y = 15
atau
Verified answer
M1 = -6persamaan garis
*tolong jadikan sbgai jawaban terbaik ^^