Question

Persamaan garis singgung (y + 3)^ = -4(x +1) di titik berabsis -5 adalah

Answer 1

(y+3)² = -4(x+1)
(y+3)² = -4(-4)
(y+3)² = 16
y²+6y++9-16 = 0
y²+6y-7 = 0
(y+7)(y-1) = 0
y = -7 atau y = 1

y=-7
(-5,-7)
(y+3)(-7+3) = -2x-2(-5)-4
(y+3)(-4) = -2x+6
-4y-12 = -2x+6
2x-4y-18 = 0
x-2y-9 = 0

y = 1
(-5,1)
(y+3)(1+3) = -2x-2(-5)-4
(y+3)(4) = -2x+6
4y+12 = -2x+6
2x+4y+6 = 0
x+2y+3 = 0