Jawab:
−32x + y − 68 = 0
Penjelasan dengan langkah-langkah:
PGS Kurva y = – x⁴ + 20 bergradien 32:
m ⇔ y' (x) = – 4x³ = 32
m ⇔ y' (x) = – x³ = 8
m ⇔ y'(x) = – x³ = 8
m ⇔ y'(x) = x = ∛-8
m ⇔ y'(x) = x = -2
y = – x⁴ + 20
y = – (-2)⁴ + 20
y = – 16 + 20
y = 4
Persamaan Garis Singgung Kurva:
y – y₁ = m (x – x₁)
y – 4 = 32 (x + 2)
y – 4 = 32x + 64
y = 32x + 68
Semoga membantu~
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Jawab:
−32x + y − 68 = 0
Penjelasan dengan langkah-langkah:
PGS Kurva y = – x⁴ + 20 bergradien 32:
m ⇔ y' (x) = – 4x³ = 32
m ⇔ y' (x) = – x³ = 8
m ⇔ y'(x) = – x³ = 8
m ⇔ y'(x) = x = ∛-8
m ⇔ y'(x) = x = -2
y = – x⁴ + 20
y = – (-2)⁴ + 20
y = – 16 + 20
y = 4
Persamaan Garis Singgung Kurva:
y – y₁ = m (x – x₁)
y – 4 = 32 (x + 2)
y – 4 = 32x + 64
y = 32x + 68
Semoga membantu~
Jawab:
Penjelasan dengan langkah-langkah: