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y = -⅓x + ⅔
m = -⅓
persamaan garis yang tegak lurus adalah
y - y1 = -1/m(x - x1)
y - 1 = -1/(-⅓) (x - 2)
y - 1 = 3(x - 2)
y - 1 = 3x - 6
y = 3x - 5