Question

Persamaan garis lurus yg tegak lurus dengan 3x + 5y +13=0 dan melalui (-3,1)adalah

Answer 1

3x + 5y + 13 = 0
5y = -3x -13
y = -3/5 x -2 3/5

gradien = -3/5
(-3,1) x1 = -3 , y1 = 1

y-y1 = m(x-x1)
y-1 = -3/5[x-(-3)]
y-1 = -3/5(x+3)
y-1 = -3/5x -9/5
y = -3/5x -1 4/5 +1
y = -3/5x -4/5