Question

Persamaan garis lurus yg melalui titik (3,-4) dan sejajar dgn garis 2x-5y-10=0
pilihannya
A.2x+5y=-14
B.5x+2y=7
C.2x-5y=26
D.5x-2y=23

Answer 1

(3,-4) = (x1,y1)
m = -a/b
= -2/-5
= 2/5

y-y1=m(x-x1)
y-(-4) = 2/5(x-3)
y+4 = 2/5(x-3)
dikali 5 agar pecahannya habis
5y+20=2(x-3)
5y+20=2x-6
=2x-5y-6-20=0
=2x-5y-26=0
=2x-5y=26 (c)