GarisGradien garis yg melalui (-3,0) dan (0,6)m1 = ∆y/∆x = (0 - 6)/(-3 - 0) m1 = -6/-3m1 = 2Tegaklurus → m2 = -1/m1 = -1/2Garis b dg m = -1/2 dan melalui (-3,0)y - 0 = -1/2 (x - (-3))2y = -x - 3x + 2y + 3 = 0 → jawaban
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Garis
Gradien garis yg melalui (-3,0) dan (0,6)
m1 = ∆y/∆x = (0 - 6)/(-3 - 0)
m1 = -6/-3
m1 = 2
Tegaklurus → m2 = -1/m1 = -1/2
Garis b dg m = -1/2 dan melalui (-3,0)
y - 0 = -1/2 (x - (-3))
2y = -x - 3
x + 2y + 3 = 0 → jawaban