Question

Persamaan deferensial yha di kalkulus 2
PD : X+YCosX + SinXY' = 0

Answer 1

SUASAAH AMAAT SOALNYA DEH
X+YCosX + SinXY' = 0

x. cosec x + y cotan x +  dy/dx=o

dy/dx + (cotan x) y = - x cosec x
solusi  dy/dx +P(x) y = Q(x)





sehingga PUPD =  

y cosec x =  int(x cosec x . cosec x) dx

y cosec x =  int(x cosec² x) dx

y cosec x =  int(x ) d(tanx)

y cosec x =  x . tan x  - int(tan x) dx = xtanx - - ln |cos x| +C