[tex]tt = \sqrt{ {c}^{2} - ( { \frac{a - b}{2} )}^{2} } \\ \sqrt{ {5}^{2} -( { \frac{12 - 6}{2} )}^{2} } = \sqrt{ {5}^{2} - {3}^{2} } \\ \sqrt{25 - 9} = \sqrt{16} = 4 \\ \\ LP \: prisma \: trapesium \\ tt(a + b) + tp(a + b + c + c) \\ 4(12 + 6) + 15(12 + 6 + 5 + 5) \\ 4(18) + 15(28) \\ 72+ 420 \\ 492 \: {cm}^{2} [/tex]
Penjelasan dengan langkah-langkah:
cari tinggi alas
t² = 5² -(12-6×1/2)²
t² = 25 - 3²
t² = 25 - 9
t² = 16
t = 4 cm
Luas alas dan atap
L = ((6×4)+(4×3))×2
L = 24 + 12 × 2
L = 72 cm
Lp = 72 + (5×15×2) + (6×15) + (15×12)
Lp = 72 + 150 + 90 + 180
Lp = 492 cm²
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[tex]tt = \sqrt{ {c}^{2} - ( { \frac{a - b}{2} )}^{2} } \\ \sqrt{ {5}^{2} -( { \frac{12 - 6}{2} )}^{2} } = \sqrt{ {5}^{2} - {3}^{2} } \\ \sqrt{25 - 9} = \sqrt{16} = 4 \\ \\ LP \: prisma \: trapesium \\ tt(a + b) + tp(a + b + c + c) \\ 4(12 + 6) + 15(12 + 6 + 5 + 5) \\ 4(18) + 15(28) \\ 72+ 420 \\ 492 \: {cm}^{2} [/tex]
Verified answer
Penjelasan dengan langkah-langkah:
cari tinggi alas
t² = 5² -(12-6×1/2)²
t² = 25 - 3²
t² = 25 - 9
t² = 16
t = 4 cm
Luas alas dan atap
L = ((6×4)+(4×3))×2
L = 24 + 12 × 2
L = 72 cm
Lp = 72 + (5×15×2) + (6×15) + (15×12)
Lp = 72 + 150 + 90 + 180
Lp = 492 cm²