[tex] \\ [/tex]
[tex] \cos2 \alpha = 1 - 2( \frac{1}{5} \sqrt{13} ) {}^{2} [/tex]
[tex] \ = 1 - 2( \frac{1}{25} \times 13)[/tex]
[tex] \ = 1 - 2( \frac{13}{25} )[/tex]
[tex] \ = 1 - \frac{26}{25} [/tex]
[tex] \ = \frac{25}{25} - \frac{26}{25} [/tex]
[tex] \bf = \boxed{ \bf- \frac{1}{25} }[/tex]
Kelas : 10
Mapel : Matematika
Bab : Bab 7 - Trigonometri
Kode : 10.2.7
Salah langsung report saja ya TvT
[tex]\tiny{ \orange{\tt ༆ \: Uzeyji}}[/tex]
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Pendahuluan
[tex] \\ [/tex]
[tex] \cos2 \alpha = 1 - 2( \frac{1}{5} \sqrt{13} ) {}^{2} [/tex]
[tex] \ = 1 - 2( \frac{1}{25} \times 13)[/tex]
[tex] \ = 1 - 2( \frac{13}{25} )[/tex]
[tex] \ = 1 - \frac{26}{25} [/tex]
[tex] \ = \frac{25}{25} - \frac{26}{25} [/tex]
[tex] \bf = \boxed{ \bf- \frac{1}{25} }[/tex]
[tex] \\ [/tex]
Pelajari lebih lanjut
[tex] \\ [/tex]
Detail jawaban
Kelas : 10
Mapel : Matematika
Bab : Bab 7 - Trigonometri
Kode : 10.2.7
Salah langsung report saja ya TvT
[tex]\tiny{ \orange{\tt ༆ \: Uzeyji}}[/tex]