Marianaz1554
Diket: r = 21 cm maka d = 42cm 1) a. kell = 22/7 x 42 = 132 cm Panjang Busur: b. AB = 90°/360° x 132 = 33 cm c. BC = 60°/360° x 132 = 22 cm d. CD = 45°/360° x 132 = 16,5 cm e. AD = 165°/360° x 132 = 60,5 cm
2) diket. Luas Juring dgn <90° = 154 cm^2 a. 150°/90° x 154 = 256,7 cm^2 b. 120°/90° x 154 = 205,3 cm^2 c. Luas triplek = 154+256,7+205,3 = 616 cm^2 d. OA = r = ? π x r^2 = Luas o 22/7 x r^2 = 616 cm^2 r^2 = 616 : 22/7 = 616 x 7/22 = 196 r = √196 = 14 cm r = 14 cm, maka d = 28 cm
1) a. kell = 22/7 x 42 = 132 cm
Panjang Busur:
b. AB = 90°/360° x 132 = 33 cm
c. BC = 60°/360° x 132 = 22 cm
d. CD = 45°/360° x 132 = 16,5 cm
e. AD = 165°/360° x 132 = 60,5 cm
2) diket. Luas Juring dgn <90° = 154 cm^2
a. 150°/90° x 154 = 256,7 cm^2
b. 120°/90° x 154 = 205,3 cm^2
c. Luas triplek = 154+256,7+205,3 = 616 cm^2
d. OA = r = ?
π x r^2 = Luas o
22/7 x r^2 = 616 cm^2
r^2 = 616 : 22/7 = 616 x 7/22 = 196
r = √196 = 14 cm
r = 14 cm, maka d = 28 cm
e. keliling = 22/7 x 28 = 88 cm