a .2×(5×4)+(4×12)+(5×12)
20+48+60=128×2=248
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= 2 × (pl + pt + lt)
= 2 × (5×4 + 5×12 + 4×12)
= 2 × (20 + 60 + 48)
= 2 × 128
= 256 cm2
b) Luas permukaan tanpa tutup
= pl + 2 × (pt + pl)
= 5×4 + 2 × (5×12 + 4×12)
= 20 + 2 × (60 + 48)
= 20 + 2 × 108
= 20 + 216
= 236 cm2
Sekian dan terim kasih
a .2×(5×4)+(4×12)+(5×12)
20+48+60=128×2=248
semoga membantu