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kecepatan v = vo + integral percepatan
v = 2i + integral [(4t)i - 6j] dt
v = 2i + (2t^2)i - (6t)j
v = [2 + 2t^2]i - (6t)j
saat t = 2,
v = [2 + 2(4)]i + 6(2)j
diperoleh vektor kecepatan sebesar
v = 10i + 12j m/s
besarnya kecepatan adalah
|v| = akar [10^2 + 12^2]
|v| = 2akar61 m/s