Perbandingan panjang, lebar, dan tinggi sebuah balok berturut-turut adalah 5:3:2. Jika volume balok 810cm3 ,, maka luas permukaan balok tersebut adalah
Kochammatmę
V = 810cm3 a,b,c - lebar, panjang dan tinggi
a = 5x b = 3x c = 2x
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damianamukti
Misalkan : p=5x l = 3x t= 2x volume = p × l × t 810cm³= 5x × 3x × 2x 810cm³ = 30x³ x³ = 27 x = 3cm p = 5(3cm) = 15cm l = 3(3cm) = 9cm t = 2(3cm) = 6cm Lp = 2((p×l)+(p×t)+(l×t)) = 2 ((15cm×9cm)+(15cm×6cm)+(9cm×6cm)) = 2(135cm²+90cm²+54cm²) = 2(279cm²) = 558cm²
a,b,c - lebar, panjang dan tinggi
a = 5x
b = 3x
c = 2x
l = 3x
t= 2x
volume = p × l × t
810cm³= 5x × 3x × 2x
810cm³ = 30x³
x³ = 27
x = 3cm
p = 5(3cm) = 15cm
l = 3(3cm) = 9cm
t = 2(3cm) = 6cm
Lp = 2((p×l)+(p×t)+(l×t))
= 2 ((15cm×9cm)+(15cm×6cm)+(9cm×6cm))
= 2(135cm²+90cm²+54cm²)
= 2(279cm²)
= 558cm²