Perbandingan panjang, lebar, dan tinggi sebuah balok berturut" adalah 5:3:2. jika volume balok 810cm kubik maka luas permukaan balok tersebut adalah..
lindaayu630
P = 15 l = 9 t = 6 Lp = 2(pl + pt +lt) =2( 15.9 + 15.6 + 9.6) = 558 cm²
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fikribahtiar
Perbandingannya = p:l:t = 5:3:2 = 5X:3X:2X volume 810 cm³ = p.l.t 810= 5X.3X.2X 810=30X³ 810/30=X³ X³ = 27 X = √27 X = 3 Jadi p = 5X = 5 x 3 = 15 cm l = 3X = 3 x 3 = 9 cm t = 2X = 2 x 3 = 6 cm jadi luas permukaan Balok = 2 x [(pxl)+(lxt)+(pxt)] = 2 x [(15 x 9)+(9 x 6)+(15 x 6)] = 2 x (135+54+90) = 2 x 179 = 358 cm²
l = 9
t = 6
Lp = 2(pl + pt +lt)
=2( 15.9 + 15.6 + 9.6)
= 558 cm²
volume 810 cm³ = p.l.t
810= 5X.3X.2X
810=30X³
810/30=X³
X³ = 27
X = √27
X = 3
Jadi p = 5X = 5 x 3 = 15 cm
l = 3X = 3 x 3 = 9 cm
t = 2X = 2 x 3 = 6 cm
jadi luas permukaan Balok = 2 x [(pxl)+(lxt)+(pxt)]
= 2 x [(15 x 9)+(9 x 6)+(15 x 6)]
= 2 x (135+54+90)
= 2 x 179
= 358 cm²
Thanks Yah?!!!