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2Πr : 2Πr¹
perb kll tetap = 2:3
Luas Lingkaran
Πr² : Πr²
2² : 3²
perb Luas jadi 4 : 9
ket Π = phi
Lingkaran (1) jari-jarinya = r1
Lingkaran (2) jari-jarinya = r2
r1 : r2 = 2 : 3
Keliling lingkaran = 2 π r
Luas lingkaran = π r²
Jawab :
a) Kllg Lingkaran (1) : Kllg Lingkaran (2) = 2 π r1 = r1 = 2 = 2 : 3
2 π r2 r2 3
b) Luas Lingk (1) : Luas Lingk (2) = π.r1² = r1² = 2² = 4 = 4 : 9
π.r2² r2² 3² 9
moga cukup jelas ^_^