Jawab:Ali+Bakri+Candra = 216
Penjelasan dengan langkah-langkah:
Diketahui:a = 5, b = 3, c = 4⇒ Ali-Candra = 18a-c = 5-4 = 1⇒ a-c = 1
Ditanya: Ali+Bakri+Candra
Ali = a×(Ali-Candra)/(a-c)Ali = 5×(18)/1➡️ Ali = 90
Candra = c×(Ali-Candra)/(a-c)Candra = 4×(18)/1➡️ Candra = 72
b/c = Bakrie/Candra3/4 = Bakrie/72Bakrie = 72×(3)/4Bakrie = 18×(3)➡️ Bakrie = 54
∴ Ali+Bakri+Candra= 90+54+72= 216
[[ KLF ]]
Nilai Ali=A
Nilai Bakri=B
Nilai Candra=C
A:B:C=5:3:4
A:C=5:4
C=4/5 A... persamaan 1
A-C=18
A=18+C.... persamaan 2
C=4/5 A
C=4/5 (18+C)
Kedua ruas dikali dengan 5
5C=4(18+C)
5C=72+4C
5C-4C=72
C=72
A=18+C=18+72=90
A:B=5:3
B=3/5 A
B=3/5 (90)=54
Nilai Ali=90
Nilai Bakri=54
Nilai Candra=72
Jumlah nilai ketiganya=90+54+72=216
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Jawab:
Ali+Bakri+Candra = 216
Penjelasan dengan langkah-langkah:
Diketahui:
a = 5, b = 3, c = 4
⇒ Ali-Candra = 18
a-c = 5-4 = 1
⇒ a-c = 1
Ditanya: Ali+Bakri+Candra
Ali = a×(Ali-Candra)/(a-c)
Ali = 5×(18)/1
➡️ Ali = 90
Candra = c×(Ali-Candra)/(a-c)
Candra = 4×(18)/1
➡️ Candra = 72
b/c = Bakrie/Candra
3/4 = Bakrie/72
Bakrie = 72×(3)/4
Bakrie = 18×(3)
➡️ Bakrie = 54
∴ Ali+Bakri+Candra
= 90+54+72
= 216
[[ KLF ]]
Nilai Ali=A
Nilai Bakri=B
Nilai Candra=C
A:B:C=5:3:4
A:C=5:4
C=4/5 A... persamaan 1
A-C=18
A=18+C.... persamaan 2
C=4/5 A
C=4/5 (18+C)
Kedua ruas dikali dengan 5
5C=4(18+C)
5C=72+4C
5C-4C=72
C=72
A=18+C=18+72=90
A:B:C=5:3:4
A:B=5:3
B=3/5 A
B=3/5 (90)=54
Nilai Ali=90
Nilai Bakri=54
Nilai Candra=72
Jumlah nilai ketiganya=90+54+72=216