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Materi : Medan Magnetik dan Induksi ElektromagnetikSub bab : Trafo
Diketahui :
Np : Ns = 2:5
Vp = 220 v
Ditanya :
a) Vs
b) Is -> Ip = 400 mA
Penyelesaian :
*Cari tegangan sekunder
a) Vp/Vs = Np/Ns
220 v/Vs = 2/5
110 v/Vs = 1/5
Vs = 550 volt
*Cari kuat arus sekunder
b) Vp/Vs = Is/Ip
220 v/550 v = Is/400 mA
2/5 = Is/400 mA
5Is = 800 mA
Is = 160 mA
Jadi, besarnya tegangan sekunder dan arus sekunder adalah 550 v dan 160 mA
semoga membantu
-vin