perbandingan diagonal suatu layang layang 2:3. Jika luas layang layang 108 cm2, berapa panjang masing masing diagonalnya?
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108 = 2n×3n×1/2
108 = 6n×1/2
6n =108×2
6n =216
n = 216÷6=36 cm
jadi, d1=2n=2×36=72cm
d2=3n=3×36=108cm
perbandingan d1:d2= 72cm:108cm
108=D1xD2/2
108=3X x 2X / 2
108=3x2
x2=36
x=akar 36 = 6 cm
D1= 6x2 =12 c m
D2=6x3 = 18cm