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3p+4q = -16
2p-q. = -18
_________ di eliminasi
Atas dikali 2
Bawah dikali 3
6p+8q= -32
6p-3q= -54
__________ _
11q = 22
q = 22/11
q = 2
Lalu km substitusikan nilai q yg sudah diketahui
Ke persamaan diatas
3p+4q = -16
3p+4(2)=-16
3p+8. = -16
3p= -16 -8
3p= -24
p= -24/3
p= -8
Maka:
Nilai dari p + q
= -8 + 2
= -6
Terima kasih