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(1) 2y - 3x = 15
(2) y = x² + 2x - 15
dari (1)
2y - 3x = 15
2y = 15 + 3x
y = (15 + 3x) / 2 ... (3)
substitusi (3) ke dalam (20
y = x² + 2x - 15
(15 + 3x) / 2 = x² + 2x - 15
15 + 3x = 2 (x² + 2x - 15)
15 + 3x = 2x² + 4x - 30
0 = 2x² + x - 45
0 = ¹/₂ (2x + 10) (2x - 9)
0 = (x + 5) (2x - 9)
x₁ = -5 → y₁ = 0
atau
x₂ = ⁹/₂ → y₂ = ⁵⁷/₄
HP = { (-5, 0) , (⁹/₂ , ⁵⁷/₄) }
p q p q
Nilai dari 2p - q
2p - q = 2 (-5) - 0 = -10 ←
2p - q = 2 (⁹/₂) - ⁵⁷/₄ = - ²¹/₄ ←